sethbeckerman5 Staff asked 13 years ago
So my goal right now is to detect the user's PHP version (not an issue), and then run an if else based on it
So if I write something like this:
the issue I'm having is I want to use PHP's anonymous functions if the user has 5.3 or greater (since they were introduced in PHP 5.3) and an alternative if they have an older version. The problem is, of course, that if a user has PHP 5.2.17 for instance, that while that if statement will never evaluate as true, a fatal error will be thrown for syntax since the anonymous function call looks like a syntax error to PHP 5.2.17
Is there a way to do something like the above? The only work around I've found is to put the stuff in the if in a new file, and the stuff in the else in another, and do something like this:
Now this will work fine, since function53.php will never be loaded for a 5.2 user. However it's not ideal to have to use separate files.
After reading the comment's to Ales's quesiton, something like this:
Will not work. PHP's compiler will run both files on compilation checking for syntax errors before execution and throw the error I'm trying to avoid. The only way for the file method to work is to dynamically pick a file based on version number. This requires a seperate file for every x.y release from PHP 4 and 5. Not ideal.
On Alex's answer, it works fine. We're talking one line of eval (required to hide the anonymous function call), versus the proposed tons of files.
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